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Question

Chemistry Question on Biomolecules

Match List I with List II
\begin{array}{|c|c|c|} \hline \text{LIST-I} & & \text{LIST-II} \\\ \hline \text{A. Glucose/NaHCO}_3/\Delta & & \text{I. Gluconic acid} \\\ \text{B. Glucose/HNO}_3 & & \text{II. No reaction} \\\ \text{C. Glucose/HI/} \Delta & & \text{III. n-hexane} \\\ \text{D. Glucose/Bromine water} & & \text{IV. Saccharic acid} \\\ \hline \end{array}
Choose the correct answer from the options given below:

A

A-IV, B-I, C-III, D-II

B

A-II, B-IV, C-III, D-I

C

A-III, B-II, C-I, D-IV

D

A-I, B-IV, C-III, D-II

Answer

A-II, B-IV, C-III, D-I

Explanation

Solution

Glucose+NaHCO3/ΔNo reaction\text{Glucose} + \text{NaHCO}_3 / \Delta \rightarrow \text{No reaction}
Glucose+HNO3Saccharic acid\text{Glucose} + \text{HNO}_3 \rightarrow \text{Saccharic acid}
Glucose+HI/Δn-hexane\text{Glucose} + \text{HI} / \Delta \rightarrow \text{n-hexane}
Glucose+Bromine waterGluconic acid\text{Glucose} + \text{Bromine water} \rightarrow \text{Gluconic acid}