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Question

Physics Question on Units and measurement

Match List-I with List-II.
\begin{array}{|c|c|c|} \hline \text{List-I} & & \text{List-II} \\\ \hline \text{A. Coefficient of viscosity} & & \text{I.} \; [M L^2 T^{-2}] \\\ \text{B. Surface Tension} & & \text{II.} \; [M L^2 T^{-1}] \\\ \text{C. Angular momentum} & & \text{III.} \; [M L^1 T^{-1}] \\\ \text{D. Rotational kinetic energy} & & \text{IV.} \; [M L^0 T^{-2}] \\\ \hline \end{array}

A

A–II, B–I, C–IV, D–III

B

A–I, B–II, C–III, D–IV

C

A–III, B–IV, C–II, D–I

D

A–IV, B–III, C–II, D–I

Answer

A–III, B–IV, C–II, D–I

Explanation

Solution

Use dimensional analysis:

Coefficient of viscosity η=FAdydt[η]=[ML1T1]\eta = \frac{F}{A} \frac{dy}{dt} \Rightarrow [\eta] = [ML^{-1}T^{-1}].

Surface Tension S.T=FL[ML0T2]S.T = \frac{F}{L} \Rightarrow [ML^{0}T^{-2}].

Angular momentum L=mvr[ML2T1]L = mvr \Rightarrow [ML^{2}T^{-1}].

Rotational kinetic energy K.E.=12Iω2[ML2T2]K.E. = \frac{1}{2} I \omega^2 \Rightarrow [ML^{2}T^{-2}].

This confirms the matching as AIIIA - III, BIVB - IV, CIIC - II, DID - I.