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Question

Chemistry Question on Thermodynamics terms

Match List I (Equations) with List II (Types of process) and select the correct option.

A

(A) \to 1 ,(B) \to 2 ,(C) \to 3 ,(D ) \to 4

B

(A) \to 3 ,(B) \to 4 ,(C) \to 2 ,(D ) \to 1

C

(A) \to 4 ,(B) \to 1 ,(C) \to 2 ,(D ) \to 3

D

(A) \to 2 ,(B) \to 1 ,(C) \to 4 ,(D ) \to 3

Answer

(A) \to 4 ,(B) \to 1 ,(C) \to 2 ,(D ) \to 3

Explanation

Solution

(A) When KP>QK_{P} > Q, the reaction goes in forward direction, i.e., the reaction is spontaneous. (B) Given, ΔG<RTlnQ\Delta G^{\circ} < R T \ln Q thus, ΔG=+\Delta G^{\circ}=+ ve and hence, the reaction is non-spontaneous. (C) At equilibrium, KP=QK_{P}=Q (D) T>ΔHΔST >\frac{\Delta H}{\Delta S} or TΔS>ΔHT \Delta S > \Delta H This condition is true for spontaneous endothermic reactions (as ΔGΔHTΔS)\Delta G \geq \Delta H-T \Delta S)