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Question: Match list-1 (atomic number of elements) with list-2 (position of elements in periodic table) and se...

Match list-1 (atomic number of elements) with list-2 (position of elements in periodic table) and select the correct answer using the codes given below the lists.

List-1List-2
A.1919
B.2222
C.3232
D.6464

A. A−1,B−2,C−3,D−4A - 1,B - 2,C - 3,D - 4
B. A−4,B−3,C−1,D−2A - 4,B - 3,C - 1,D - 2
C. A−4,B−1,C−3,D−2A - 4,B - 1,C - 3,D - 2
D. A−2,B−1,C−3,D−4A - 2,B - 1,C - 3,D - 4

Explanation

Solution

In order to answer the question we have to know about modern periodic table.
In this table elements are classified into four parts as ′s′,′p′,′d′ and f−block's','p','d'\,and\,f - block elements according to their electronic configuration and last shell electron.

Complete step by step answer:
Modern periodic table is a display of the elements which are arranged by their atomic number, electronic configuration, chemical and physical properties. It has eighteen columns called groups and seven rows called periods.
Column number 1 and 2 (⊥A and 2A)( \bot A\,and\,2A)are known a s-block elements , 3 to 12 (III B,WB,13−18(III A,IV A,VA,VIA,O)3\,to\,12\,(III\,B,WB,13 - 18(III\,A,IV\,A,VA,VIA,O)as p-block elements and another thirsty elements, stay at the bottom of the periodic table are known as f-block elements and their valence electron goes into ′s′,′p′,′d ′and ′f′'s','p','d\,'and\,'f'orbital’s simultaneously.
General electronic configuration of ‘s block
: ns2 (n=2to7)  [where, n=no. of row]:\,n{s^2}\,(n = 2to7)\,\,[where,\,n = no.\,of\,row]
′p′  block: ns2 np1−6( n=2to 6)'p'\,\,block:\,n{s^2}\,n{p^{1 - 6}}(\,n = 2to\,6)
d   block:(n−1)d1−10 ns0−2( n=4to 7)d\,\,\,block:(n - 1){d^{1 - 10}}\,n{s^{0 - 2}}(\,n = 4to\,7)
f   block:(n−2)f1−14(n−1)d6−1 ns0−2( n=6to 7)f\,\,\,block:(n - 2){f^{1 - 14}}(n - 1){d^{6 - 1}}\,n{s^{0 - 2}}(\,n = 6to\,7)
Here electronic configuration atomic number 19−[Ar]4s′19 - [Ar]4s'

22−[Ar]4s2 3d232−[Ar]4s2 3d10 4p2and 64−[×e]4f7 5d1 6s2 22 - [Ar]4{s^2}\,3{d^2} 32 - [Ar]4{s^2}\,3{d^{10}}\,4{p^2} and\,64 - [ \times e]4{f^7}\,5{d^1}\,6{s^2}

Where Ar and Xe are noble gas with atomic number 18 and 54.
So from the above explanation we clearly understand that atomic number 19- s-block, 22-block, 32-p block and 64-f block element.

The answer is option (B)

Note:
“Periodic table” is a great revolution of science. Still now 108108 elements have been categorized in similar physical and chemical properties.
From the table we can easily find out the characteristics of any element.
Maximum contain of electrons of ′s′,′p′,′d′ and ′f′'s','p','d'\,and\,'f' orbital (on sub level) is 2,6,10  and 142,6,10\,\,and\,14orderly.