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Question: Mass of oil is \(11040\,\,kg\) and volume is \(12\,\,{m^3},\) its density would be: A. \(92\,\,kg\...

Mass of oil is 11040  kg11040\,\,kg and volume is 12  m3,12\,\,{m^3}, its density would be:
A. 92  kg  m−392\,\,kg\,\,{m^{ - 3}}
B. 920  kg  m−3920\,\,kg\,\,{m^{ - 3}}
C. 9.2  kg  m−39.2\,\,kg\,\,{m^{ - 3}}
D. 1.08  kg  10−31.08\,\,kg\,\,{10^{ - 3}}

Explanation

Solution

To solve this question,first we have to know about the relation between density,mass and volume which is density =massvolume = \dfrac{{mass}}{{volume}} after knowing this we can put the values of given quantities and arrive at the solution.

Complete step by step answer:
Let the density of the oil is ρℓ,{\rho _\ell }, mass is m and volume is v respectively. It is given that m=11040  kgm = 11040\,\,kg and V=12  m3V = 12\,\,{m^3} so the density of the oil is given by
PL=MV{P_L} = \dfrac{M}{V}
Putting the values of M and V into the equation …….(i)
Hence, PL=MV{P_L} = \dfrac{M}{V}
Or PL=1104012{P_L} = \dfrac{{11040}}{{12}}
Or, PL=920  kg /m3{P_L} = 920\,\,kg\,/{m^3}
Hence, option (B) is correct.

Additional Information:
1. An object from a comparatively dense material such as iron will have less volume than an object of equal mass made from some less dense substance such as water.
2. The SI unit of density is kilogram per cubic meter i.e. kg/m3kg/{m^3}.
3. The Gaussian unit of density is in gram per cubic centimeter (1gm/cm3).\left( {1gm/c{m^3}} \right).Also one gram per cubic centimeter (1gm/cm3)=\left( {1gm/c{m^3}} \right) = one gram per milliliter(1gm/ml)\left( {1gm/ml} \right).

Note: The density is the measurement of mass per unit volume. The average density of an object is equal to its total mass divided by its total volume.