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Question: Mass of moon is \(7.34 \times 10^{22}kg.\) If the acceleration due to gravity on the moon is 1.4m/s<...

Mass of moon is 7.34×1022kg.7.34 \times 10^{22}kg. If the acceleration due to gravity on the moon is 1.4m/s2, the radius of the moon is (G=6.667×1011Nm2/kg2)(G = 6.667 \times 10^{- 11}Nm^{2}/kg^{2})

A

0.56×104m0.56 \times 10^{4}m

B

1.87×106m1.87 \times 10^{6}m

C

1.92×106m1.92 \times 10^{6}m

D

1.01×108m1.01 \times 10^{8}m

Answer

1.87×106m1.87 \times 10^{6}m

Explanation

Solution

We know g=GMR2g = \frac{GM}{R^{2}}

R=GMg=6.67×1011×7.34×10221.4=1.87×106m\therefore R = \sqrt{\frac{GM}{g}} = \sqrt{\frac{6.67 \times 10^{- 11} \times 7.34 \times 10^{22}}{1.4}} = 1.87 \times 10^{6}m.