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Question

Chemistry Question on Some basic concepts of chemistry

Mass of acetic acid required to neutralize 100 cc of 0.1 N NaOH solution is

A

0.6 g

B

1.2 g

C

2.4 g

D

1.8 g

Answer

0.6 g

Explanation

Solution

For neutralization, no. of gram equivalents of acid should be equal to no. of gram equivalents of base. No. of gram equivalents of NaOH =100×0.11000=0.01 = \frac{100 \times 0.1}{1000} = 0.01 Now, wemassofacid=0.01 \frac{w}{emass\, of\, acid}= 0.01 w=60×0.01=0.6gw = 60 \times 0.01 = 0.6 g