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Question

Physics Question on Nuclei

Mass numbers of two nuclei are in the ratio of 4:34 : 3. Their nuclear densities will be in the ratio of

A

4:34 : 3

B

(34)13\bigg(\frac{3}{4}\bigg)^{\frac{1}{3}}

C

1:11:1

D

(43)13\bigg(\frac{4}{3}\bigg)^{\frac{1}{3}}

Answer

1:11:1

Explanation

Solution

R=R0A13R = R_0A^{\frac{1}{3}}

R1R2=(A1A2)13⇒ \frac{R_1}{R_2} = \bigg(\frac{A_1}{A_2}\bigg)^\frac{1}{3}

=(43)13= \bigg(\frac{4}{3}\bigg)^{\frac{1}{3}}

Ratio of density between two nuclei: ρ1ρ2=A1V1A2V2\frac{ρ_1}{ρ_2} = \frac{\frac{A_1}{V_1}}{\frac{A_2}{V_2}}

= (A1A2)×(R2R1)3\bigg(\frac{A_1}{A_2}\bigg) \times \bigg(\frac{R_2}{R_1}\bigg)^3

= 1:11 : 1