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Question

Physics Question on Nuclei

Mass numbers of the elements A,B,CA, B, C and DD are 30,60,9030, 60, 90 and 120120 respectively. The specific binding energy of them are 5MeV,8.5MeV,8MeV5 \, MeV, 8.5 \, MeV, 8 \, MeV and 7MeV7 \, MeV respectively. Then, in which of the following reaction/s energy is released ? (a) D2BD \rightarrow 2B (b) CB+AC \rightarrow B + A (c) B2AB \rightarrow 2 A

A

only in (a)

B

in (b), (c)

C

in (a), (c)

D

in (a), (b) and (c)

Answer

only in (a)

Explanation

Solution

(1) ΔE=2×60×8.5120×7=180MeV\Delta E=2 \times 60 \times 8.5-120 \times 7=180\, MeV
(2) ΔE=60×8.5+30×590×8=60MeV\Delta E=60 \times 8.5+30 \times 5-90 \times 8=-60 \,MeV
(3) ΔE=2×30×560×8.5=105MeV\Delta E=2 \times 30 \times 5-60 \times 8.5=-105 \,MeV
Hence, energy is released in (1) only.