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Question: Mars has a diameter of approximately \(0.5\) times that of earth and mass is \(0.1\) times that of e...

Mars has a diameter of approximately 0.50.5 times that of earth and mass is 0.10.1 times that of earth. The surface gravitational field strength on mars as compared to that of earth is a factor of
A. 0.10.1
B. 0.20.2
C. 2.02.0
D. 0.40.4

Explanation

Solution

In order to solve this question, we should know about gravitational field strength of a planet, Gravitational field strength is a measure of acceleration on a body falling freely under the force of gravity on a planet, we will use the general formula of gravitational field strength and will compare of these two planets mars and earth.

Formula Used:
If MM is the mass of a planet and RR is the radius of a planet and GG be the gravitational constant and gg represents the gravitational field strength then g=GMR2g = \dfrac{{GM}}{{{R^2}}}.

Complete step by step answer:
According to the question we have given, assume Mmars(and)Mearth{M_{mars}}(and){M_{earth}} denote the mass of mars and earth. and Rmars(and)Rearth{R_{mars}}(and){R_{earth}} denote the radii of these two planets.
Mmars=0.1Mearth{M_{mars}} = 0.1{M_{earth}}
and diameters of two planets can be written as R=D2R = \dfrac{D}{2} and it is given that
Dmars=0.5Dearth{D_{mars}} = 0.5{D_{earth}}
Dmars2=0.5(Dearth)2\Rightarrow \dfrac{{{D_{mars}}}}{2} = \dfrac{{0.5({D_{earth}})}}{2}
Rmars=0.5Rearth\Rightarrow {R_{mars}} = 0.5{R_{earth}}
Now for planet earth using the formula g=GMR2g = \dfrac{{GM}}{{{R^2}}} we have,
gearth=GMearthRearth2{g_{earth}} = \dfrac{{G{M_{earth}}}}{{{R_{earth}}^2}}
for planet mars we have,
gmars=GMmarsRmars2{g_{mars}} = \dfrac{{G{M_{mars}}}}{{{R_{mars}}^2}}
putting the values of parameters we get,
gmars=(0.1)GMearth(0.5)2Rearth2{g_{mars}} = \dfrac{{(0.1)G{M_{earth}}}}{{{{(0.5)}^2}{R_{earth}}^2}}
gmars=0.10.25gearth\Rightarrow {g_{mars}} = \dfrac{{0.1}}{{0.25}}{g_{earth}}
gmars=1025gearth\Rightarrow {g_{mars}} = \dfrac{{10}}{{25}}{g_{earth}}
gmars=0.4gearth\therefore {g_{mars}} = 0.4{g_{earth}}

Hence, the correct option is D.

Note: It should be remembered that, the value of acceleration due to gravity on each planet is different and larger the acceleration due to gravity of a planet the more the energy needed to escape the gravitational field of that planet. Free fall means when a body is released to fall under the force of gravity with zero initial velocity.