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Question

Question: Mark the position of the revolving line when it has traced out the following angles A. \(1185{}^\c...

Mark the position of the revolving line when it has traced out the following angles
A. 11851185{}^\circ
B. 150g{{150}^{g}}

Explanation

Solution

Hint: In order to solve this question, we have to convert the angles into degrees if they are not given in degrees. An angle in radians is converted into degrees by using the formula, Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9. After that we will try to write the given angle in radian and then in the form of nπ+θn\pi +\theta , and we will be able to trace the line.

Complete step-by-step answer:
In this question, we have been asked to trace the position of the revolving line of some angles. For that, we will first convert the angles into radians from degrees and then express it in the form of nπ+θn\pi +\theta , where n is a natural number. So, let us consider each part of the question separately.
A. 11851185{}^\circ
Here, we will first convert 11851185{}^\circ into radian, for that we will use the concept of π radians=180\pi \text{ }radians=180{}^\circ . And we can also write it as,
π180radians=1 1=π180radians \begin{aligned} & \dfrac{\pi }{180{}^\circ }radians=1{}^\circ \\\ & \Rightarrow 1{}^\circ =\dfrac{\pi }{180{}^\circ }radians \\\ \end{aligned}
Now, we will multiply both sides of the above equation by 1185, so we get,
1185=π180×1185 radians 1185=79π12 radians \begin{aligned} & 1185{}^\circ =\dfrac{\pi }{180}\times 1185\text{ }radians \\\ & \Rightarrow 1185{}^\circ =\dfrac{79\pi }{12}\text{ }radians \\\ \end{aligned}
Now, we will express 79π12\dfrac{79\pi }{12} in terms of nπ+θn\pi +\theta . So, we will write the same as,
79π12=72π+7π12 79π12=6π+7π12=3×2π+7π12 \begin{aligned} & \dfrac{79\pi }{12}=\dfrac{72\pi +7\pi }{12} \\\ & \Rightarrow \dfrac{79\pi }{12}=6\pi +\dfrac{7\pi }{12}=3\times 2\pi +\dfrac{7\pi }{12} \\\ \end{aligned}
So, now we can say that 1185=6π+7π12 radians1185{}^\circ =6\pi +\dfrac{7\pi }{12}\text{ }radians. Now, for tracing the revolving line of the angle, we have to have a 2D graph, which has the left and right axis as negative and positive x axis, whereas the axis perpendicular to them is positive and negative y axis. As the angle is 6π+7π126\pi +\dfrac{7\pi }{12} and we know that 1 revolution is completed at 2π2\pi , it means that the line will complete 3 revolutions and then it will be either in the first quadrant or in the second quadrant, depending on the value of 7π12\dfrac{7\pi }{12}. We can write it as 7π12=π2+π12\dfrac{7\pi }{12}=\dfrac{\pi }{2}+\dfrac{\pi }{12}. Since it is in the form of π2+θ\dfrac{\pi }{2}+\theta , it will be in the second quadrant at an angle of π12\dfrac{\pi }{12} from positive y axis. Hence, we can represent it as line OA in the figure given below.

B. 150g{{150}^{g}}
Here, we have been given an angle in the gradient and therefore to convert it to radians, we have to first convert it into degrees. We know that Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9, so we can write it as,
150g in degrees=150×0.9 150g in degrees=135 \begin{aligned} & {{150}^{g}}\text{ in degrees}=150\times 0.9 \\\ & \Rightarrow {{150}^{g}}\text{ in degrees}=135{}^\circ \\\ \end{aligned}
Now, we will convert 135135{}^\circ into radians to express it in nπ+θn\pi +\theta form. We know that 180=π radians180{}^\circ =\pi \text{ }radians, and therefore we can write it as, 1=π180radians1{}^\circ =\dfrac{\pi }{180}radians. So, we can write,
135=π180×135 radians 135=3π4 radians \begin{aligned} & 135{}^\circ =\dfrac{\pi }{180}\times 135\text{ }radians \\\ & \Rightarrow 135{}^\circ =\dfrac{3\pi }{4}\text{ }radians \\\ \end{aligned}
Now, we will express 3π4\dfrac{3\pi }{4} in terms of nπ+θn\pi +\theta . So, we will write the same as,
3π4=0π+3π4 3π4=0+3π4 \begin{aligned} & \dfrac{3\pi }{4}=\dfrac{0\pi +3\pi }{4} \\\ & \Rightarrow \dfrac{3\pi }{4}=0+\dfrac{3\pi }{4} \\\ \end{aligned}
Now, we can say that 150g=3π4radians{{150}^{g}}=\dfrac{3\pi }{4}radians. Now, for tracing the line, we can see that it will either lie in the first quadrant or in the second quadrant depending on 3π4\dfrac{3\pi }{4}. We can write it as 3π4=π2+π4\dfrac{3\pi }{4}=\dfrac{\pi }{2}+\dfrac{\pi }{4}. Since it is in the form of π2+θ\dfrac{\pi }{2}+\theta , it will be in the second quadrant, at an angle of π4\dfrac{\pi }{4} from the positive y axis. Hence, we can represent the line as line OB as in the figure given below.


Note: Here, we have expressed angles in the form of nπ+θn\pi +\theta , because in the coordinate axis we have four quadrants and after an angle of 360360{}^\circ , we again reach the first quadrant and then the angles start repeating. This makes it easier to understand and represent the angles in the correct quadrants. So, care must be taken not to make mistakes in this portion.