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Question

Question: Mark the position of the revolving line when \({{420}^{g}}\) it has traced out the following angles....

Mark the position of the revolving line when 420g{{420}^{g}} it has traced out the following angles.
A. 420g{{420}^{g}}
B. 875g{{875}^{g}}

Explanation

Solution

Hint: To solve this question, we have to convert the angles into degrees if they are not given in degrees by using the relation between radian and degrees, which is, Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9. Then we will try to write the given angle in the form of nπ+θn\pi +\theta , and then we will be able to trace the line on a 2D graph on which the positive x axis represents even π\pi angles and negative y axis represents odd π\pi angles.

Complete step-by-step answer:
In this question, we have been asked to trace the position of the revolving line of some angles. For that, we will first convert the angles into degrees by using the relation, Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9 and then convert the degrees into radians to express it in the form of nπ+θn\pi +\theta , where n is a natural number. So, let us consider each part of the question individually.
A. 420g{{420}^{g}}
Here we have angels in the gradian form, and so we have to convert it into radians. So, we will first convert it into degrees. We know that, Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9. So, we can write as,
420g in degrees=420×0.9 420g in degrees=378 \begin{aligned} & {{420}^{g}}\text{ in degrees}=420\times 0.9 \\\ & \Rightarrow {{420}^{g}}\text{ in degrees}=378{}^\circ \\\ \end{aligned}
Now, we will convert 378378{}^\circ into radians to express that in nπ+θn\pi +\theta form. We know that 180=π radians180{}^\circ =\pi \text{ }radians, and therefore we can write it as, 1=π180radians1{}^\circ =\dfrac{\pi }{180}radians. So, we will get,
378=378×π180radians 378=21π10radians \begin{aligned} & 378{}^\circ =378\times \dfrac{\pi }{180}radians \\\ & \Rightarrow 378{}^\circ =\dfrac{21\pi }{10}radians \\\ \end{aligned}
Now, we will express 21π10\dfrac{21\pi }{10} in terms of nπ+θn\pi +\theta . And so, we will write the same as,
21π10=20π+π10 21π10=2π+π10 \begin{aligned} & \dfrac{21\pi }{10}=\dfrac{20\pi +\pi }{10} \\\ & \Rightarrow \dfrac{21\pi }{10}=2\pi +\dfrac{\pi }{10} \\\ \end{aligned}
Now, we can say that 420g=2π+π10radians{{420}^{g}}=2\pi +\dfrac{\pi }{10}radians. Now, for tracing the line, we know that one revolution is completed when angle is 2π2\pi , so here one complete revolution has been completed by the line. Then, we can see that it will either lie in the first quadrant or in the second quadrant, depending on π10\dfrac{\pi }{10}, which cannot be expressed as the sum of some angles with π2\dfrac{\pi }{2}. So, it will lie in the first quadrant at an angle of π10\dfrac{\pi }{10} from the positive x axis. Hence, we can represent the line as line OA as in the figure given below.

B. 875g{{875}^{g}}
Here, we can see that we have been given an angle in the gradient, so we have to convert it into radians. For that we will first convert it into degrees. We know that, Degree=Gradian×0.9\text{Degree}=\text{Gradian}\times 0.9. So, we can write as,
875g in degrees=875×0.9 875g in degrees=787.5 \begin{aligned} & {{875}^{g}}\text{ in degrees}=875\times 0.9 \\\ & \Rightarrow {{875}^{g}}\text{ in degrees}=787.5{}^\circ \\\ \end{aligned}
Now, we will convert 787.5787.5{}^\circ into radians in order to express the same in nπ+θn\pi +\theta form. We know that 180=π radians180{}^\circ =\pi \text{ }radians, and so, we can write it as, 1=π180radians1{}^\circ =\dfrac{\pi }{180}radians. Hence, we will write,
787.5=787.5×π180 radians 787.5=35π8 radians \begin{aligned} & 787.5{}^\circ =787.5\times \dfrac{\pi }{180}\text{ }radians \\\ & \Rightarrow 787.5{}^\circ =\dfrac{35\pi }{8}\text{ }radians \\\ \end{aligned}
Now, we will express 35π8\dfrac{35\pi }{8} in terms of nπ+θn\pi +\theta . So, for that, we will write the same as,
35π8=32π+3π8 35π8=4π+3π8=2×2π+3π8 \begin{aligned} & \dfrac{35\pi }{8}=\dfrac{32\pi +3\pi }{8} \\\ & \Rightarrow \dfrac{35\pi }{8}=4\pi +\dfrac{3\pi }{8}=2\times 2\pi +\dfrac{3\pi }{8} \\\ \end{aligned}
Now, we can say that 875g=4π+3π8radians{{875}^{g}}=4\pi +\dfrac{3\pi }{8}radians. We know that one revolution is completed when angle is 2π2\pi , so here 2 complete revolutions have been completed by the line. Now, for tracing the line, we can see that it will either lie in the first quadrant or in the second quadrant, depending on the value of 3π8\dfrac{3\pi }{8}. We cannot represent it in the form of π2+θ\dfrac{\pi }{2}+\theta , so it will lie in the first quadrant at an angle of 3π8\dfrac{3\pi }{8} from the positive x axis. Hence, we can represent the line as line OB as in the figure given below.

Note: Here, we have expressed the angles in the form of nπ+θn\pi +\theta , because in coordinate axis we have four quadrants and after angle of 360=2π360{}^\circ =2\pi , we will again reach the first quadrant and then the angles start repeating. Also, while converting degrees into radian, we need to remember that π radians=180\pi \text{ }radians=180{}^\circ . If we make any silly mistake while writing the angles, we will get a different quadrant and also our figure will change completely, so we must be careful.