Solveeit Logo
Login

Question

Question: Mark the correct Nernst equation for the given cell. \[Fe_{(s)}|Fe^{2 +}(0.001M)||H^{+}(1M)|H_{2(g)...

Mark the correct Nernst equation for the given cell.

Fe(s)∣Fe2+(0.001M)∣∣H+(1M)∣H2(g)(1bar)∣Pt(s)Fe_{(s)}|Fe^{2 +}(0.001M)||H^{+}(1M)|H_{2(g)}(1bar)|Pt_{(s)}

A

Ecell=Eºcell−0.5912log⁡[Fe2+][H+]2[Fe][H2]E_{cell} = Eº_{cell} - \frac{0.591}{2}\log\frac{\lbrack Fe^{2 +}\rbrack\lbrack H^{+}\rbrack^{2}}{\lbrack Fe\rbrack\lbrack H_{2}\rbrack}

B

Ecell=Eºcell−0.5912log⁡[Fe][H+]2[Fe2+][H2]E_{cell} = Eº_{cell} - \frac{0.591}{2}\log\frac{\lbrack Fe\rbrack\lbrack H^{+}\rbrack^{2}}{\lbrack Fe^{2 +}\rbrack\lbrack H_{2}\rbrack}

C

Ecell=Eºcell−0.05912log⁡[Fe2+][H2][Fe][H+]2E_{cell} = Eº_{cell} - \frac{0.0591}{2}\log\frac{\lbrack Fe^{2 +}\rbrack\lbrack H_{2}\rbrack}{\lbrack Fe\rbrack\lbrack H^{+}\rbrack^{2}}

D

Ecell=Eºcell−0.05912log⁡[Fe][H2][Fe2+][H+]2E_{cell} = Eº_{cell} - \frac{0.0591}{2}\log\frac{\lbrack Fe\rbrack\lbrack H_{2}\rbrack}{\lbrack Fe^{2 +}\rbrack\lbrack H^{+}\rbrack^{2}}

Answer

Ecell=Eºcell−0.05912log⁡[Fe2+][H2][Fe][H+]2E_{cell} = Eº_{cell} - \frac{0.0591}{2}\log\frac{\lbrack Fe^{2 +}\rbrack\lbrack H_{2}\rbrack}{\lbrack Fe\rbrack\lbrack H^{+}\rbrack^{2}}

Explanation

Solution

At anode Fe→Fe2+(0.001M)+2e−Fe \rightarrow Fe^{2 +}(0.001M) + 2e^{-}

Atcathode2H+(1M)+2e−→H2(1atm)Atcathode2H^{+}(1M) + 2e^{-} \rightarrow H_{2}(1atm)

Netreaction:Fe+2H+→Fe2++H2Netreaction:Fe + 2H^{+} \rightarrow Fe^{2 +} + H_{2}

Nernst equation for the given cell,

Ecell=Eºcell−0.05912log⁡[Fe2+][H2][Fe][H+]2E_{cell} = Eº_{cell} - \frac{0.0591}{2}\log\frac{\lbrack Fe^{2 +}\rbrack\lbrack H_{2}\rbrack}{\lbrack Fe\rbrack\lbrack H^{+}\rbrack^{2}}