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Question: Magnetic intensity for an axial point due to a short bar magnet of magnetic moment M is given by...

Magnetic intensity for an axial point due to a short bar magnet of magnetic moment M is given by

A

μ04π×Md3\frac { \mu _ { 0 } } { 4 \pi } \times \frac { M } { d ^ { 3 } }

B

μ04π×Md2\frac { \mu _ { 0 } } { 4 \pi } \times \frac { M } { d ^ { 2 } }

C

μ02π×Md3\frac { \mu _ { 0 } } { 2 \pi } \times \frac { M } { d ^ { 3 } }

D

μ02π×Md2\frac { \mu _ { 0 } } { 2 \pi } \times \frac { M } { d ^ { 2 } }

Answer

μ02π×Md3\frac { \mu _ { 0 } } { 2 \pi } \times \frac { M } { d ^ { 3 } }

Explanation

Solution

Ba=μ04π2Md3=μ02πMd3B _ { a } = \frac { \mu _ { 0 } } { 4 \pi } \frac { 2 M } { d ^ { 3 } } = \frac { \mu _ { 0 } } { 2 \pi } \frac { M } { d ^ { 3 } }