Question
Question: Magnetic flux linked with a stationary loop resistance \( R \) varies with time \( t \) as \( \phi =...
Magnetic flux linked with a stationary loop resistance R varies with time t as ϕ=at(T−t) . Amount of heat generated in loop during time interval T is
(A) 3RaT
(B) 3Ra2T2
(C) Ra2T2
(D) 3Ra2T3
Solution
Since in this question we have to find the amount of heat generated in the required time interval so for this we will use the flux equation which is given by at(T−t) . And as we know that the induced emf is the negative derivative of flux. So substituting these values in the Heat equation we will get to the solution.
Formula used:
Flux is given by
X=at(T−t)
Here, X will be the flux produced.
a , will be the acceleration
t , will be the time.
Complete step by step solution:
Since from the formula of flux, we have the equation given as, X=at(T−t)
And the induced emf will be given by e=−dtdX
And on substituting the above values and differentiating it, the emf will be equal to
⇒e=2at−at
Since thee heat produced during this time period is given by
⇒H=0∫TRe2dt
Now on substituting the values, we get the equation as
⇒H=0∫TR(2at−at)2dt
Here, the above numerator can be written by using this formula (a−b)2=a2+b2−2ab , so the equation will become
⇒H=0∫TR4a2t2+a2T2−4a2Ttdt
So by solving the integration, the above integration will become
⇒H=3R1(4a2T3+3a2T3−6a2T3)
Further solving more, the above equation will become
⇒H=3Ra2T3
Hence, the amount of heat generated in the loop during the time interval T is 3Ra2T3 .
Therefore, the option (D) is correct.
Note:
There are mainly two factors on which the amount of heat produced in the wire depends upon and those factors are the current flowing in the wire and the resistance of the wire. Also while solving this type of question we have to be clear about the terms in the formula as they are being restructured and then used as we have used in the above part.