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Question

Physics Question on Electromagnetic induction

Magnetic flux linked with a stationary loop of resistance R varies with respect to time during the time period T as follows: ϕ=at(Tt)\phi=at(T-t) the amount of heat generated in the loop during that time (inductance of the coil is negligible) is

A

aT3R\frac{aT}{3R}

B

a2T23R\frac{a^2T^2}{3R}

C

a2T2R\frac{a^2T^2}{R}

D

a2T33R\frac{a^2T^3}{3R}

Answer

a2T33R\frac{a^2T^3}{3R}

Explanation

Solution

Given that ϕ=at(Tt)\phi = at (T - t) induced emf, E=dϕdt=ddt[at(Tt)]E = \frac{d \phi}{dt} = \frac{d}{dt} [ at(T - t)] = at(01)+a(Tt)=a(T2t)at (0-1) + a (T - t) = a(T - 2t) So, indeced emf is also a function of time. \therefore Heat generated in time TT is H=0TE2Rdt=a2R0T(T2t)2dt=a2T33RH = \int^T_0 \frac{E^2}{R} dt = \frac{a^2}{R} \int^T_0 (T - 2t)^2 dt = \frac{a^2 T^3}{3R}