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Question

Physics Question on Moving charges and magnetism

Magnetic field intensity HH at the centre of a circular loop of radius rr carrying current II is

A

RI\frac {R}{I} oersted

B

2πIr\frac {2\pi I} {r} oersted

C

I2πr\frac {I} {2 \pi r} oersted

D

2πrI\frac {2\pi r}{I} oersted

Answer

2πIr\frac {2\pi I} {r} oersted

Explanation

Solution

H=μ0I2r=μ04π×2πIrH=\frac{\mu_{0} I}{2 r}=\frac{\mu_{0}}{4 \pi} \times \frac{2 \pi I}{r}
In emu system μ04π=1\frac{\mu_{0}}{4 \pi}=1
So, H=2πIrH=\frac{2 \pi I}{r} oersted