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Question

Physics Question on Moving charges and magnetism

Magnetic field intensity at the centre of coil of 50 turns, radius 0.5 m and carrying a current of 2 A, is

A

3×10−5 T3 \times {10}^ {-5} \,T

B

1.25×10−4 T1.25 \times {10}^ {-4} \,T

C

0.5×10−5 T0.5 \times {10}^ {-5} \,T

D

4×106 T4 \times {10}^ {6 }\,T

Answer

1.25×10−4 T1.25 \times {10}^ {-4} \,T

Explanation

Solution

B=μ0(Ni)2r=4π×10−7×50×22×0.5=1.256×10−4TB= \frac{ {\mu}_0 (Ni)}{2r} = \frac{4 \pi \times {10}^{-7} \times 50 \times 2 }{ 2 \times 0.5 } = 1.256 \times {10}^{-4} T