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Question

Physics Question on Moving charges and magnetism

Magnetic field at the centre of a circular loop of area AA is BB. The magnetic moment of the loop will be

A

BA2μ0π\frac{B A^{2}}{\mu_{0} \pi}

B

BA3/2μ0π\frac{B A^{3 / 2}}{\mu_{0} \pi}

C

BA3/2μ0π1/2\frac{B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}

D

2BA3/2μ0π1/2\frac{2 B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}

Answer

2BA3/2μ0π1/2\frac{2 B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}

Explanation

Solution

B=μ04π2πir=μ0i2rB=\frac{\mu_{0}}{4 \pi} \frac{2 \pi i}{r}=\frac{\mu_{0} i}{2 r} or i=2Brμ0i=\frac{2 B r}{\mu_{0}} Also, A=πr2A=\pi r^{2} or r=(Aπ)1/2r=\left(\frac{A}{\pi}\right)^{1 / 2} Magnetic moment, M=iA=2Brμ0AM=i A=\frac{2 B r}{\mu_{0}} A =2BAμ0×(Aπ)1/2=\frac{2 B A}{\mu_{0}} \times\left(\frac{A}{\pi}\right)^{1 / 2} =2BA3/2μ0π1/2=\frac{2 B A^{3 / 2}}{\mu_{0} \pi^{1 / 2}}