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Question: Magnetic field at a distance \(r\) from an infinitely long straight conductor carrying a steady curr...

Magnetic field at a distance rr from an infinitely long straight conductor carrying a steady current varies as:
A) 1r\dfrac{1}{{\sqrt r }}
B) 1r\dfrac{1}{r}
C) 1r3\dfrac{1}{{{r^3}}}
D) 1r\dfrac{1}{{\sqrt r }}

Explanation

Solution

Use Biot-Savart law, which gives the magnetic field generated for constant electric current to get the expression for the magnetic field at a distance r from an infinitely long straight conductor carrying a steady current. From the expression, you will get the rr dependence term.

Formula used:
Biot-Savart law:
The magnetic field of steady line current is given by:
B(r)=μ04πIdl^×r^r2\vec B(r) = \dfrac{{{\mu _0}}}{{4\pi }}I\int {\dfrac{{d\hat l \times \hat r}}{{{r^2}}}}
Where,
B(r)\vec B(r) denotes the magnetic field at a distance rr,
μ0{\mu _0} is the permeability of free space,
II is the amount of steady current through the conductor,
dl^d\hat l is a unit element of length along the conductor,
r^\hat r is the unit vector along with the distance from the source to the point,
rr is the perpendicular distance between the conductor and the point.

Complete step by step solution:
Given,
The wire is infinite.
The point is at a distance rr from the wire.
To find: Dependence of the magnetic field on rr at the point,
Step 1
Use Biot-Savart law to get the expression of the magnetic field at point P at a distance r(perpendicularly) from a straight wire segment carrying a steady current I and whose ends makes an angle θ\theta and θ2{\theta _2} respectively (shown in the figure) as:
B=μ0I4πr(sinθ2sinθ1)B = \dfrac{{{\mu _0}I}}{{4\pi r}}\left( {\sin {\theta _2} - \sin {\theta _1}} \right)
Using the right-hand rule, get the direction of the magnetic field as out of the plane.
Step 2
For infinite long wire notice that θ1=π2{\theta _1} = - \dfrac{\pi }{2}and θ1=π2{\theta _1} = - \dfrac{\pi }{2}. Substituting the values you’ll get:
B=μ0I4πr(sin(π2)sin(π2))=μ0I4πr(1(1))=μ0I2πrB = \dfrac{{{\mu _0}I}}{{4\pi r}}\left( {\sin \left( {\dfrac{\pi }{2}} \right) - \sin \left( { - \dfrac{\pi }{2}} \right)} \right) = \dfrac{{{\mu _0}I}}{{4\pi r}}(1 - ( - 1)) = \dfrac{{{\mu _0}I}}{{2\pi r}}

\therefore Magnetic field will vary as 1r\dfrac{1}{r}. Hence option (B) is the correct answer.

Note:
While finding the magnetic field keep an eye on its direction also. You will get a sense of direction just using the right-hand rule. Place the thumb, the first finger, and middle finger perpendicularly to each other. If the first finger denotes the current direction and the middle finger denotes the distance vector direction then the thumb will give you the direction of the magnetic field.