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Question

Physics Question on Electromagnetic induction

Magnetic energy density in an inductor is given by

A

UB=B2/2μ0U_{B}=B^{2}/2\mu_{0}

B

UB=B2×2μ0U_{B}=B^{2} \times 2\mu_{0}

C

UB=2B2/μ0U_{B}=2B^{2}/\mu_{0}

D

UB=B2+2μ0U_{B}=B^{2}+2\mu_{0}

Answer

UB=B2/2μ0U_{B}=B^{2}/2\mu_{0}

Explanation

Solution

Magnetic energy density in the inductor is
UB=B22μ0U_{B}=\frac{B^{2}}{2 \mu_{0}}