Question

$M{n^{2 + }}$ ​is identified by its oxidation to a salt giving pink colour in solution.
Which of the following is correct?
(a) The pink colour is due to the formation of $MnO_4^ -$
(b) Oxidising agent used is $B{r_2}$ water or $Pb{O_2}/{H^ + }$
(c) Oxidised $M{n^{2 + }}$ changes to ${K_2}Mn{O_4}$ (green) by $KOH$
A. All are correct
B. Only (a) and (b) are correct
C. Only (b) and (c) are correct
D. Only (c) is correct

Answer 1

Hint : The loss of electrons during a molecule, atom or ion response is oxidation. Oxidation occurs when a molecule, atom or ion increases its oxidation status. The opposite process, which takes place when electric gains or the oxidation condition of an atom, molecule or ion decreases, is called a reduction.

Complete Step By Step Answer:
The process of electrons loss of any substance is oxidation. The process of addition of oxygen is also oxidation. The oxidation process is known as oxidation since it is added to the compound.
(a) $Mn\left( {II} \right)$ is oxidized to pink coloured permanganate ion $(MnO_4^ - )$
(b) Bromine water or acidified lead oxide $\left( {Pb{O_2}/{H^ + }{\text{ }}} \right)$ can be used as oxidizing agents.
(c) Pink coloured permanganate ions react with KOH to form green coloured manganate ions $(MnO_4^{2 - })$ .
Hence, all the given statements are true
So, the correct option is: (A) All are correct.

Note :
$M{n^{2 + }}$ is a divalent metal cation with manganese as the metal. It functions as a cofactor. It's a manganese cation, a divalent metal cation, and a monatomic cation. Manganese has a molar mass of $54.94g/mol$ and is a transition metal. Manganese is an essential mineral for human health, as it aids in growth, metabolism, and the antioxidant system. Excessive manganese consumption, on the other hand, is linked to manganism, a neurodegenerative condition characterised by dopaminergic neuronal death and parkinsonian-like symptoms.