QuestionReportMathematics Question on limits and derivativesltx→∞(x2+5x+3x2+x+3)13lt_{x\rightarrow\infin}(\frac{x^2+5x+3}{x^2+x+3})^{\frac{1}{3}}ltx→∞(x2+x+3x2+5x+3)31 isAe4Be2Ce3D1Answere4ExplanationSolutionThe correct option is (A): e4