Question

Lowering of vapour pressure of 30% of aqueous solution of glucose. (in mmHg)
Given: PH2O = 760 mm of Hg

Answer 1

Correct answer is 729 mmHg.

$\frac{760-x}{x}=\frac{(\frac{30}{180})}{(\frac{70}{18})}=\frac{3}{70}$

$x=728.7$ mm HG $\approx \, 729$ mmHG