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Question

Question: Lowering of vapour pressure is highest for....

Lowering of vapour pressure is highest for.

A

Urea

B

0.1M0.1M glucose

C

0.1MMgSO40.1MMgSO_{4}

D

0.1MBaCl20.1MBaCl_{2}

Answer

0.1MBaCl20.1MBaCl_{2}

Explanation

Solution

P0PsP0=molality×(1-α+xα+yα)\frac{P^{0} - P_{s}}{P^{0}} = \text{molality} \times (\text{1-}\alpha + x\alpha + y\alpha) the value of P0PsP^{0} - P_{s} is maximum for BaCl2BaCl_{2}.