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Physics Question on Moving charges and magnetism

Lorentz force is given by the following formula

A

F⃗=qE⃗\vec{ F }=q \vec{ E }

B

F⃗=q(V⃗×B⃗)\vec{ F }=q(\vec{ V } \times \vec{ B })

C

F⃗=qE⃗+q(V⃗×B⃗)\vec{ F }=q \vec{ E }+q(\vec{ V } \times \vec{ B })

D

F⃗=qE⃗+q(B⃗×V⃗)\vec{ F }=q \vec{ E }+q(\vec{ B } \times \vec{ V })

Answer

F⃗=qE⃗+q(V⃗×B⃗)\vec{ F }=q \vec{ E }+q(\vec{ V } \times \vec{ B })

Explanation

Solution

Lorentz force for a moving charged particle is F⃗=qE⃗+qvB sin⁡θ\vec{F}=q\vec{E}+qvB\,\sin \theta =qE⃗Electric force+q(v⃗×B⃗Magnetic force)= \underset{\text{Electric force}}{q\vec{E}} + \underset{\text{Magnetic force}}{q(\vec{v} \times \vec{B}})