Question
Question: \[{logsec}x(\sec x + \tan x) + c\]...
logsecx(secx+tanx)+c
A
∫(2x+1)22xdx=
B
21log(2x+1)+2(2x+1)1+c
C
21log(2x+1)−2(2x+1)1+c
D
2log(2x+1)+2(2x+1)1+c
Answer
2log(2x+1)+2(2x+1)1+c
Explanation
Solution
log(cos−1x)+c
−log(cos−1x)+c
−2(cos−1x)21+c