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Question

Question: \[{logsec}x(\sec x + \tan x) + c\]...

logsecx(secx+tanx)+c{logsec}x(\sec x + \tan x) + c

A

2x(2x+1)2dx=\int_{}^{}{\frac{2x}{(2x + 1)^{2}}dx =}

B

12log(2x+1)+12(2x+1)+c\frac{1}{2}\log(2x + 1) + \frac{1}{2(2x + 1)} + c

C

12log(2x+1)12(2x+1)+c\frac{1}{2}\log(2x + 1) - \frac{1}{2(2x + 1)} + c

D

2log(2x+1)+12(2x+1)+c2\log(2x + 1) + \frac{1}{2(2x + 1)} + c

Answer

2log(2x+1)+12(2x+1)+c2\log(2x + 1) + \frac{1}{2(2x + 1)} + c

Explanation

Solution

log(cos1x)+c\log(\cos^{- 1}x) + c

log(cos1x)+c- \log(\cos^{- 1}x) + c

12(cos1x)2+c- \frac{1}{2(\cos^{- 1}x)^{2}} + c