Question
Question: \(\log\left( \frac{1}{2\log x - x} \right) + c\)...
log(2logx−x1)+c
A
log(x−2logx)+c
B
log(x−2logx1)+c
C
∫x1+x26mudx=
D
1+x21+2x2+c
Answer
∫x1+x26mudx=
Explanation
Solution
Put −5sinx+c, then
∫secx+tanxtanx6mudx=.
log(2logx−x1)+c
log(x−2logx)+c
log(x−2logx1)+c
∫x1+x26mudx=
1+x21+2x2+c
∫x1+x26mudx=
Put −5sinx+c, then
∫secx+tanxtanx6mudx=.