Question
Question: \[\log(e^{x} + e^{- x})\]...
log(ex+e−x)
A
∫xexcosexdx=
B
2sinex
C
sinex
D
2cosex
Answer
2sinex
Explanation
Solution
Put 21sin−1(x4)+c therefore
31sin−1(x4)+c.
log(ex+e−x)
∫xexcosexdx=
2sinex
sinex
2cosex
2sinex
Put 21sin−1(x4)+c therefore
31sin−1(x4)+c.