Question
Question: \(\log(e^{2x} + 1) - x + c\)...
log(e2x+1)−x+c
A
log(e2x+1)+c
B
∫logtan2xcosecx6mudx=
C
log(logtan2x)+c
D
None of these
Answer
∫logtan2xcosecx6mudx=
Explanation
Solution
Putting a=−4π,6mub= we get
∫sinx+cosxdx=
logtan(8π+2x)+c
logtan(8π−2x)+c