Question
Question: \(\log_{e}x + 2\tan^{- 1}x + c\)...
logex+2tan−1x+c
A
logex2+11+c
B
loge{x(x2+1)}+c
C
∫1−xdx
D
21−x+c
Answer
loge{x(x2+1)}+c
Explanation
Solution
Put log[log(logx)]+c
Hence log(xlogx)+c
logex+2tan−1x+c
logex2+11+c
loge{x(x2+1)}+c
∫1−xdx
21−x+c
loge{x(x2+1)}+c
Put log[log(logx)]+c
Hence log(xlogx)+c