QuestionReportMathematics Question on Logarithmslogxb−logxa=logxc−logxblog_xb-log_xa=log_xc-log_xblogxb−logxa=logxc−logxb ∴ac=∴ac=∴ac=Aa2a^2a2Bb2b^2b2Cc2c^2c2DNoneAnswerb2b^2b2ExplanationSolutionThe correct option is (B): b2b^2b2.