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Question

Mathematics Question on Logarithms

logx2+logx22+logx23++logx2n=n(n+1)2log_x2+log_x2^2+log_x2^3+………+ log_x2^n=\frac {n(n+1)}{2}, then x=x=

A

n

B

1

C

5

D

2

Answer

2

Explanation

Solution

The correct option is (D): 2.