Question
Question: \[\log x + \log(\log x)\]...
logx+log(logx)
A
∫x1+logx dx
B
logx=t
C
1+logx=t
D
None of these
Answer
1+logx=t
Explanation
Solution
Put ∫2xcos3x2sinx2dx=
∫x(1+logx)2dx=∫t2dt 41cos4x2+c
logx+log(logx)
∫x1+logx dx
logx=t
1+logx=t
None of these
1+logx=t
Put ∫2xcos3x2sinx2dx=
∫x(1+logx)2dx=∫t2dt 41cos4x2+c