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Question

Question: \[\log x + \log(\log x)\]...

logx+log(logx)\log x + \log(\log x)

A

1+logxx dx\int_{}^{}{\frac{1 + \log x}{x}\ }dx

B

logx=t\log x = t

C

1+logx=t1 + \log x = t

D

None of these

Answer

1+logx=t1 + \log x = t

Explanation

Solution

Put 2xcos3x2sinx2dx=\int_{}^{}{2x\cos^{3}x^{2}\sin x^{2}dx =}

(1+logx)2xdx=t2dt\int \frac { ( 1 + \log x ) ^ { 2 } } { x } d x = \int t ^ { 2 } d t 14cos4x2+c\frac{1}{4}\cos^{4}x^{2} + c