Question
Mathematics Question on Conic sections
Locus of the point of intersection of perpendicular tangents to the circle x2+y2=16 is
A
x2+y2=8
B
x2+y2=32
C
x2+y2=64
D
x2+y2=16.
Answer
x2+y2=32
Explanation
Solution
Answer (b) x2+y2=32
Locus of the point of intersection of perpendicular tangents to the circle x2+y2=16 is
x2+y2=8
x2+y2=32
x2+y2=64
x2+y2=16.
x2+y2=32
Answer (b) x2+y2=32