Question

Locus of a point at which the circles x² + y² –2x –2y –7 = 0 and x² + y² + 8x + 6y = 0 subtend equal angles, is –

• A. The complete circle 16x²+16y²–122x–104y–175=0
• B. A minor arc of the circle 16x²+16y²–122x–104y–175=0
• C. A major arc of the circle 16x²+16y²–122x–104y–175 = 0
• D. Exactly two points on the circle 16x² +16y² –122x – 104y –175 = 0

Answer 1

Answer: (C)

A major arc of the circle 16x²+16y²–122x–104y–175 = 0

Answer 2

Two circles cut each other, also locus is obtained by 2tan^–1$\left( \frac{r_{1}}{\sqrt{s_{1}}} \right)$ = 2 tan^–1$\left( \frac{r_{2}}{\sqrt{s_{2}}} \right)$

which is 16x² + 16y² – 122 x – 104y – 175 = 0 whose centre lies outside smaller circle .