Question

$ln \frac{k_2}{k_1} = - \frac{E_a}{R} \bigg( \frac{1}{T_2} - \frac{1}{T_1} \bigg)$Consider the following statements : $1$. increase in concentration of reactant increases the rate of a zero order reaction $2$. rate constant $k$ is equal to collision frequency $A$ if $E_a = 0$. $3$. rate constant $k$ is equal to collision frequency $A$ if $E_a = \infty$ $4$. In $k\, vs\, T$ is a straight line $5$. In $k\, vs\, 1/T$ is a straight line Correct statements are

• A. $1$ and $4$
• B. $2$ and $5$
• C. $3$ and $4$
• D. $2$ and $3$

Answer 1

Answer: (B)

$2$ and $5$

Answer 2

Answer (b) $2$ and $5$