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Question: The Van der Waals constants for gases A, B and C are as follows | Gas | a[/atm L² mol⁻²] | b[/L mol...

The Van der Waals constants for gases A, B and C are as follows

Gasa[/atm L² mol⁻²]b[/L mol⁻¹]
A8.210.050
B4.1050.030
C1.6820.040

Which gas has (i) the highest critical temperature, (ii) the largest molecular volume, and (iii) most ideal behaviour around 500 K?

A

(i) A, (ii) A, (iii) C

B

(i) B, (ii) A, (iii) A

C

(i) C, (ii) B, (iii) B

D

(i) A, (ii) C, (iii) B

Answer

(i) A, (ii) A, (iii) C

Explanation

Solution

  1. Highest Critical Temperature (TcT_c): TcabT_c \propto \frac{a}{b}.

    • Gas A: 8.210.050=164.2\frac{8.21}{0.050} = 164.2
    • Gas B: 4.1050.030136.83\frac{4.105}{0.030} \approx 136.83
    • Gas C: 1.6820.040=42.05\frac{1.682}{0.040} = 42.05 Gas A has the highest ab\frac{a}{b} ratio, hence the highest TcT_c.
  2. Largest Molecular Volume: This is directly proportional to the Van der Waals constant 'b'.

    • Gas A: b=0.050b = 0.050 L mol⁻¹
    • Gas B: b=0.030b = 0.030 L mol⁻¹
    • Gas C: b=0.040b = 0.040 L mol⁻¹ Gas A has the largest 'b' value, hence the largest molecular volume.
  3. Most Ideal Behaviour around 500 K: Ideal behaviour is observed near the Boyle temperature (TB=aRbT_B = \frac{a}{Rb}).

    • Gas A: TB=8.210.0821×0.050=2000T_B = \frac{8.21}{0.0821 \times 0.050} = 2000 K
    • Gas B: TB=4.1050.0821×0.0301667T_B = \frac{4.105}{0.0821 \times 0.030} \approx 1667 K
    • Gas C: TB=1.6820.0821×0.040512T_B = \frac{1.682}{0.0821 \times 0.040} \approx 512 K Gas C's Boyle temperature (512 K) is closest to 500 K, indicating it will behave most ideally at this temperature.