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Question: Liquids A and B are at 30<sup>0</sup>C and 20<sup>0</sup>C respectively. When mixed in equal masses,...

Liquids A and B are at 300C and 200C respectively. When mixed in equal masses, the temperature of the mixture is found to be 260C, The specific heats of A and B are in the ratio of-

A

3 : 2

B

1 : 1

C

2 : 3

D

4 :3

Answer

3 : 2

Explanation

Solution

msA (30–26) = msB (26–20)

Ž 4sA = 6sB

\ sAsB=64=32\frac{s_{A}}{s_{B}} = \frac{6}{4} = \frac{3}{2}