Question

Line, any point on which is equidistant from the lines x+y= 1, 7x – y = 6

• A. 2x – 6y + 1 = 0
• B. 2x + 6y – 1 = 0
• C. 12x + 4y – 11 = 0
• D. None of these

Answer 1

Answer: (C)

12x + 4y – 11 = 0

Answer 2

Line must be bisector lines

i.e. $\frac{x + y–1}{\sqrt{2}}$ = ± $\frac{7x–y–6}{\sqrt{50}}$

Ю 2x – 6y – 1 = 0 or 12x + 4y – 11 = 0