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Question

Question: $\lim_{x \to \frac{\pi}{2}} \left( \frac{\int_{x^3}^{(\pi/2)^3} (\sin(2t^{1/3}) + \cos(t^{1/3})) dt}...

limxπ2(x3(π/2)3(sin(2t1/3)+cos(t1/3))dt(xπ2)2)\lim_{x \to \frac{\pi}{2}} \left( \frac{\int_{x^3}^{(\pi/2)^3} (\sin(2t^{1/3}) + \cos(t^{1/3})) dt}{(x-\frac{\pi}{2})^2} \right)

Answer

9π28\frac{9\pi^2}{8}

Explanation

Solution

The limit is of the indeterminate form 00\frac{0}{0}. L'Hopital's Rule is applied twice. The derivative of the numerator is found using the Fundamental Theorem of Calculus and the chain rule. After the first application, the limit remains 00\frac{0}{0}, necessitating a second application of L'Hopital's Rule. The derivatives of the resulting numerator and denominator are calculated, and evaluating them at x=π2x = \frac{\pi}{2} yields the final answer.