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Question: $\lim_{x \to 0} \frac{(1+sinx)^{\frac{1}{2024}}+(1-tanx)^{\frac{1}{2024}}}{x^3}$...

limx0(1+sinx)12024+(1tanx)12024x3\lim_{x \to 0} \frac{(1+sinx)^{\frac{1}{2024}}+(1-tanx)^{\frac{1}{2024}}}{x^3}

Answer

Does not exist

Explanation

Solution

To evaluate the limit limx0(1+sinx)12024+(1tanx)12024x3\lim_{x \to 0} \frac{(1+\sin x)^{\frac{1}{2024}}+(1-\tan x)^{\frac{1}{2024}}}{x^3}, we first evaluate the numerator and the denominator as xx approaches 00.

  1. Evaluate the numerator as x0x \to 0:
    Let N(x)=(1+sinx)12024+(1tanx)12024N(x) = (1+\sin x)^{\frac{1}{2024}}+(1-\tan x)^{\frac{1}{2024}}.
    As x0x \to 0, sinxsin0=0\sin x \to \sin 0 = 0 and tanxtan0=0\tan x \to \tan 0 = 0.
    So, N(x)(1+0)12024+(10)12024=112024+112024=1+1=2N(x) \to (1+0)^{\frac{1}{2024}} + (1-0)^{\frac{1}{2024}} = 1^{\frac{1}{2024}} + 1^{\frac{1}{2024}} = 1+1=2.

  2. Evaluate the denominator as x0x \to 0:
    Let D(x)=x3D(x) = x^3.
    As x0x \to 0, D(x)03=0D(x) \to 0^3 = 0.

  3. Determine the form of the limit:
    The limit is of the form 20\frac{2}{0}. This indicates that the limit will be either ++\infty, -\infty, or does not exist. To determine this, we need to examine the one-sided limits.

  4. Analyze the one-sided limits:

    • Right-hand limit (RHL): As x0+x \to 0^+, xx is a small positive number. Therefore, x3x^3 is also a small positive number (x30+x^3 \to 0^+). The numerator approaches a positive value, 2.
      limx0+(1+sinx)12024+(1tanx)12024x3=20+=+\lim_{x \to 0^+} \frac{(1+\sin x)^{\frac{1}{2024}}+(1-\tan x)^{\frac{1}{2024}}}{x^3} = \frac{2}{0^+} = +\infty.

    • Left-hand limit (LHL): As x0x \to 0^-, xx is a small negative number. Therefore, x3x^3 is also a small negative number (x30x^3 \to 0^-). The numerator approaches a positive value, 2.
      limx0(1+sinx)12024+(1tanx)12024x3=20=\lim_{x \to 0^-} \frac{(1+\sin x)^{\frac{1}{2024}}+(1-\tan x)^{\frac{1}{2024}}}{x^3} = \frac{2}{0^-} = -\infty.

  5. Conclusion:
    Since the right-hand limit (++\infty) and the left-hand limit (-\infty) are not equal, the limit does not exist.

Explanation of the solution:
The numerator approaches 2 as x0x \to 0, while the denominator approaches 0. This results in a limit of the form 20\frac{2}{0}. Evaluating the one-sided limits, we find that the right-hand limit is ++\infty (since x30+x^3 \to 0^+) and the left-hand limit is -\infty (since x30x^3 \to 0^-). As the one-sided limits are not equal, the overall limit does not exist.