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Question: \[\lim_{x \rightarrow a}\frac{\log\{ 1 + (x - a)\}}{(x - a)} =\]...

lim⁡x→alog⁡{1+(x−a)}(x−a)=\lim_{x \rightarrow a}\frac{\log\{ 1 + (x - a)\}}{(x - a)} =

A

–1

B

2

C

1

D

–2

Answer

1

Explanation

Solution

Let x – a = y, when x→a,y→0,x \rightarrow a,y \rightarrow 0,

The given limit = lim⁡y→0log⁡{1+y}y=1\lim_{y \rightarrow 0}\frac{\log\{ 1 + y\}}{y} = 1.