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Question

Question: \[\lim_{h \rightarrow 0}\frac{\log_{10}(1 + h)}{h} =\]...

lim⁡h→0log⁡10(1+h)h=\lim_{h \rightarrow 0}\frac{\log_{10}(1 + h)}{h} =

A

1

B

log⁡10e\log_{10}e

C

log⁡e10\log_{e}10

D

None of these

Answer

log⁡10e\log_{10}e

Explanation

Solution

lim⁡h→0log⁡e(1+h)h.\lim_{h \rightarrow 0}\frac{\log_{e}(1 + h)}{h}. 1log⁡e10=log⁡10e\frac{1}{\log_{e}10} = \log_{10}e.