Question

\lim_{x\to0} e^{x}-\dfrac{1}{3}×(1-e^{2x})$$=?

• A. $\dfrac{-1}{6}$
• B. $\dfrac{1}{6}$
• C. $1$
• D. $0$
• E. $\dfrac{-1}{3}$

Answer 1

Answer: (C)

$1$

Answer 2

$\lim_{x\to0} e^{x}-\dfrac{1}{3}×(1-e^{2x})$

Now substituting $X=0$ and on simplification we get,

$= e^0-\dfrac{1}{3}(1-e^{2.0})$

$=1-0$

$=1$ (Ans)