Question

$lim(x→\frac{x}{2}) tan^2x((2sin^2x+3sinx+4)^{\frac{1}{2}}-(sin^2x+6sinx+2)^{\frac{1}{2}}$ is equal to.

• A. 1/12
• B. -1/18
• C. -1/12
• D. 1/6

Answer 1

Answer: (A)

1/12

Answer 2

The correct option is(A): 1/12.