(\lim\limits\_{x→0} \frac {e^{|2sinx|}-2|sinx|-1}{x^2}) is | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

$\lim\limits_{x→0} \frac {e^{|2sinx|}-2|sinx|-1}{x^2}$ is

A

Doesn’t exist

B

2

C

1

D

-1

Answer

2

Explanation

Solution

The correct option is (B): 2