QuestionReportMathematics Question on Limitslimt→0sin2t8t2+4t\lim\limits_{t\rightarrow0}\frac{\sin2t}{8t^2+4t}t→0lim8t2+4tsin2t is equal toA12\frac{1}{2}21B25\frac{2}{5}52C16\frac{1}{6}61D13\frac{1}{3}31E1Answer12\frac{1}{2}21ExplanationSolutionThe correct option is (A): 12\frac{1}{2}21