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Question

Mathematics Question on limits and derivatives

limt3x2+16x+392x2+7x+3\lim\limits_{t\rightarrow-3}\frac{x^2+16x+39}{2x^2+7x+3} is equal to

A

2

B

83\frac{8}{3}

C

83\frac{-8}{3}

D

-2

E

0

Answer

-2

Explanation

Solution

The correct option is (D): -2