Question

$\lim\limits_{n \to \infty} (\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+…+\frac{1}{5n})=$

• A. $\frac{π}{4}$
• B. $tan^{-1}3$
• C. $tan^{-1}2$
• D. $\frac{π}{2}$

Answer 1

Answer: (C)

$tan^{-1}2$

Answer 2

The correct answer is Option (C) : $tan^{-1}2$